Getting all Zimbra Task Through SOAP

For example you want to fetch all task list which has branch in it as this picture. tasks_tree

You can fetch them using soap call Search for filter recursively task folder from root dir (/) and GetFolder for fetch task detail, here’s the example script of using mentioned soap call.

	__author__ = ('Imam Omar Mochtar', 'iomarmochtar@gmail.com')

	from ozpy.mailbox import Mailbox
	import sys
	from pprint import pprint
	import os

	"""
	Example of fetching Zimbra task and task list (recursively).
	"""

	class MyMailbox(Mailbox):

	def get_task(self, folder):
	"""
	Fetch task detail using SearchRequest
	https://files.zimbra.com/docs/soap_api/8.7.11/api-reference/zimbraMail/Search.html
	"""
	body = {
	"sortBy":"taskDueAsc",
	"tz":{"id":"Asia/Bangkok"},
	"locale":{"_content":"en_US"},
	"offset":0,
	"limit":100,
	"query":"in:\"{}\"".format(folder),
	"types":"task",
	"needExp":1
	}
	urn = "urn:zimbraMail"
	return self.send("Search", body, urn)

	def get_task_folders(self):
	"""
	Get list of task folder using GetFolderRequest
	https://files.zimbra.com/docs/soap_api/8.7.11/api-reference/zimbraMail/GetFolder.html
	"""
	urn = "urn:zimbraMail"
	body = {
	'folder': {'path': '/'},
	'view': 'task'
	}
	return self.send("GetFolder", body, urn)


	mbx = MyMailbox(
	username="omar@jabetto.lab",
	password="kacangitem",
	soapurl="https://192.168.113.75/service/soap",
	)


	def fetch(name, instance):
	"""
	Fetch task and sub-task recursively
	"""
	name = os.path.join(name, instance['name'])
	# print out task folder path
	print("{} {}".format("-"*10,name))
	task_req = mbx.get_task(name)

	# iterrate all task within task folder if any
	if task_req.has_key('task'):
	for task in task_req['task']:
	print('* {} - progress: {} % - location: {}'.format(
	task['name'],
	task['percentComplete'],
	task['loc']
	))

	# loop if there are subfolder
	if instance.has_key("folder"):
	for folder in instance['folder']:
	fetch(name, folder)

	response = mbx.get_task_folders()

	# get parent of task folder
	for parent_folder in response['folder'][0]['folder']:
	fetch("", parent_folder)